I do not have specification of the belt. The seller did not specify the producer. The Gates document does not mention T2.5 belts so I cannot use that as an approximation. (Regardless we do not agree how to interpret the Gates document.) It was a T2.5 belt. Its width was 6mm. Its length was 1.480m when it was tensioned with force of 190N. Then I increased the force to 280N. That made the belt to stretch to the final length of 1.4825m (1.4825m - 1.480m = 0.0025m = 2.5mm). So how much would this belt stretch if it was 1m long and the applied force was 1N? For that we need to divide the measured elongation of 2.5mm by the force difference and the length of the belt.Quote
A2
Did you mean:
A 1.0 meter span, of a T2.5 belt, with a 280 N tensile force (62.95 pound-force) elongated by 2.5 mm?
This does not make sense, show your math.Quote
hercek
That corresponds to elontagion of about 0.02mm per 1 meter of belt and 1 newton of force.
2.5 / (280-190) / 1.48 ≅ 0.02
So if it would be 1m long and the force was 1N then the belt would elongate by 0.02mm.
Yes, it is about 5 grade math and you are doing it wrong.Quote
A2
FYI: this is 5th grade math.
I show you the first error. The rest does not make sense to follow since it is already wrong after the first error:
Here is your expression B:
Since the equivalence relation is transitive we can deduce (I assume N stands for Newton):Quote
A2
B: 124105648 * Newton * meter^2 ; = ( Tensile Modulus ) = 124105648 N/meter².
124105648 * Newton * meter² = 124105648 * Newton/meter²
Now we can devide by 124105648*Newton:
meter² = 1/meter²
Now we can multiply by meter²:
meter⁴ = 1
Which is a contradiction.
I proofed by contradiction that what you have writen for expression B is not correct.
